# @stem_antics on Instagram

- **Type:** Video
- **Original URL:** https://www.instagram.com/p/DXmcrlDAFQv
- **Gondola URL:** https://gondola.cc/posts/64883920-stem-antics-instagram
- **Thumbnail:** https://img.gondola.cc/tr:w-,h-,fo-auto/postThumbnails/5bbab33274.jpg
- **Posted:** 2026-04-26T15:59:11.000+00:00
- **Account Owner:** Stem Antics (@stem_antics) — https://gondola.cc/stem_antics

## Caption

Here’s the challenge: each frog sits on a vertex of a cube, leaving exactly one corner empty. A move is only allowed if a frog jumps over another frog—landing at the point that is the reflection of its position across the jumped frog.

In math terms: if frog A jumps over frog B, its new position is
👉 A′ = 2B − A
This is a geometric reflection (or a 180° rotation around B).

Sounds simple… but here’s the twist:
Can you create a sequence of these reflections so that any frog lands exactly on the one empty vertex?

⸻

💡 What’s really happening under the hood:

* Each corner of the cube can be represented as coordinates like (0,1) in 3D → binary vectors in {0,1}³
* Each jump preserves a hidden invariant (a property that doesn’t change), related to parity and vector sums
* The system behaves like a constrained transformation group over discrete space

This is where geometry meets algebra—and intuition often fails.

⸻

🧠 Try it before reading the comments:
Is it possible… or is there a hidden rule that makes it impossible?

#STEM #MathPuzzle #Geometry #DiscreteMath #ProblemSolving

## Stats

- **Views:** 5,178
- **Likes:** 262
- **Shares:** 0
- **Comments:** 3

## Tags

stem, mathpuzzle, geometry, problemsolving, discretemath

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